# Maths

posted by .

2014 numbers are placed along the circumference of a circle. When any five successive numbers are added, the total is always 40. What are these 2014 numbers?

Please explain how you figured this out. Working is really appreciated.

• Maths -

Looks to me like they could all be 8. Are there any restrictions on the values allowed?

2014 is not a multiple of 5, so there is no cycle of 5 numbers which repeats.

## Similar Questions

1. ### math

Working on patterns. There is a diagram. Its a rectangle with the numbers 10, 16, 23 in each corner. Inside the rectangle is a circle and inside the circle are the numbers 9, 12, 24. The directions say to place the numbers 8 to 26 …
2. ### Math

Working on patterns. There is a diagram. Its a rectangle with the numbers 10, 16, 23 in each corner. Inside the rectangle is a circle and inside the circle are the numbers 9, 12, 24. The directions say to place the numbers 8 to 26 …
3. ### MATH

Working on patterns. There is a diagram. Its a rectangle with the numbers 10, 16, 23 in each corner. Inside the rectangle is a circle and inside the circle are the numbers 9, 12, 24. The directions say to place the numbers 8 to 26 …
4. ### math

Working on patterns. There is a diagram. Its a rectangle with the numbers 10, 16, 23 in each corner. Inside the rectangle is a circle and inside the circle are the numbers 9, 12, 24. The directions say to place the numbers 8 to 26 …
5. ### maths

how to write 04 feb 2014 in 5 letters without using numbers.
6. ### Math

Working on patterns. There is a diagram. Its a rectangle with the numbers 10, 16, 23 in each corner. Inside the rectangle is a circle and inside the circle are the numbers 9, 12, 24. The directions say to place the numbers 8 to 26 …
7. ### math

25 August 2014 write in five letters without using numbers
8. ### maths

How do You write 22nd november 2014 in 5 letter without using numbers
9. ### Maths- Proof

The question is: Prove algebraically that the difference between the squares of any two consecutive even numbers is always a multiple of 4. My working was: Let the numbers be n and n + 2 (n+2)^2 - (n)^2 =n^2 + 4n + 4 - n^2 =4n + 4 …
10. ### Maths

1^2014 + 2^2014 + 3^2014 + 4^2014 + 5^2014 divided by 5, remains ______

More Similar Questions