check my arctan please
posted by Anonymous
arctan(1/12)= 4.763 rounded to the nearest tenth degree, which is 4.8? because arctan=inv tan

DrBob222
right. 4.8 degrees.
Respond to this Question
Similar Questions

limiting position of the particle
A particle moves along the x axis so that its position at any time t>= 0 is given by x = arctan t What is the limiting position of the particle as t approaches infinity? 
Calculus
Note that pi lim arctan(x ) =  x > +oo 2 Now evaluate / pi \ lim arctan(x )   x x > +oo \ 2 / I'm not exactly sure how to attempt it. I have tried h'opital's rule but I don't believe you can use it here. Any help … 
calculus
Let f be a function defined by f(x)= arctan x/2 + arctan x. the value of f'(0) is? 
calc
also: integral of tan^(1)y dy how is integration of parts used in that? 
Math
Arrange these in order from least to greatest: arctan(sqrt3), arctan 0, arctan(1/2) So far I got the first two values, arctan(sqrt3), and that's 150 degrees. Arctan 0 would be zero degrees. I'll use just one answer for now, but I … 
calculus
Now we prove Machin's formula using the tangent addition formula: tan(A+B)= tanA+tanB/1tanAtanB. If A= arctan(120/119) and B= arctan(1/239), how do you show that arctan(120/119)arctan(1/239)=arctan1? 
Trig
URGENT, Please answer this question: give the value of: Tan(Arctan x+1/x1+Arctan x1/x) 
calculus
h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du= ? 
precal
The values of x that are solutions to the equation cos^(2)x=sin2x in the interval [0, pi] are a. arctan(1/2) only b. arctan(1/2) and pi c. arctan(1/2) and 0 d. arctan(1/2) and (pi/2) e. arctan(1/2), o, and (pi/2) 
PreCalculus
Simplify arctan 1/3 + arctan 2/3(round to the nearest degree).