X is a solution,of dibasic of H2X. G is a solution containing 1.00g of NaOH in 250cm3 of solution . 24.60cm3 of solution F required 25.00cm3 of solution G . From your result and information provided above. (I)concentration of G in mol/dm3 (ii) concentration of F in mol/dm3 (iii) molar mass. Of acid H2X given that 100cm3 of solution F contained 0.495g of acid (H-1.00,O-6,Na-23)
To find the concentration of solution G in mol/dm³:
Step 1: Calculate the number of moles of NaOH in solution G.
We know that the molar mass of NaOH is 22.99 + 16.00 + 1.008 = 39.998 g/mol.
Given that 1.00 g of NaOH is present in 250 cm³ of solution G, we can find the number of moles by dividing the mass by the molar mass:
Number of moles of NaOH = 1.00 g / 39.998 g/mol = 0.0250 mol.
Step 2: Convert the volume of solution G to dm³.
The given volume is 250 cm³, so we need to convert it to dm³ by dividing by 1000:
Volume of solution G = 250 cm³ / 1000 = 0.250 dm³.
Step 3: Calculate the molarity (concentration) of solution G.
Molarity = Number of moles / Volume of solution in dm³.
Molarity of solution G = 0.0250 mol / 0.250 dm³ = 0.100 mol/dm³.
Therefore, the concentration of solution G is 0.100 mol/dm³.
To find the concentration of solution F in mol/dm³:
Given that 24.60 cm³ of solution F required 25.00 cm³ of solution G, we can assume the concentrations of both solutions are equal.
Therefore, the concentration of solution F is also 0.100 mol/dm³.
To find the molar mass of the acid H2X:
Given that 100 cm³ of solution F contained 0.495 g of acid (H-1.00, O-16.00, Na-23.00), we need to calculate the number of moles of the acid.
Step 1: Calculate the molar mass of the acid.
The molar mass of H2X can be calculated by adding the atomic masses of hydrogen (H) and oxygen (O) in one molecule:
Molar mass of H2X = 2(1.008) + 16.00 = 18.016 g/mol.
Step 2: Calculate the number of moles of the acid.
Number of moles = Mass / Molar mass.
Number of moles of acid = 0.495 g / 18.016 g/mol = 0.0274 mol.
Therefore, the molar mass of the acid (H2X) is approximately 18.016 g/mol.
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To find the answers to the given question, we need to solve the concentration and molar mass of the solutions. Let's break down each part step by step:
(i) Concentration of G in mol/dm3:
The given solution G contains 1.00g of NaOH in 250cm3 of solution. To find the concentration in mol/dm3, we need to convert grams to moles and then divide it by the volume in dm3.
1. Calculate the number of moles of NaOH:
- NaOH molar mass: 1(atomic mass of Na) + 16(atomic mass of O) + 1(atomic mass of H) = 40 g/mol
- Moles of NaOH = mass of NaOH / molar mass of NaOH
= 1.00g / 40g/mol
= 0.025 mol
2. Calculate the concentration:
- Concentration of G = Moles / Volume in dm3
= 0.025 mol / (250 cm3 * 1 dm3/1000 cm3)
= 0.1 mol/dm3
Therefore, the concentration of G is 0.1 mol/dm3.
(ii) Concentration of F in mol/dm3:
From the given information, we know that 24.60 cm3 of solution F required 25.00 cm3 of solution G. Since the volumes used are the same, we can assume the ratio of their concentrations is equal to the ratio of their required volumes.
Let the concentration of F be x mol/dm3.
Volume ratio: 24.60 cm3 F / 25.00 cm3 G
Concentration ratio: x mol/dm3 F / 0.1 mol/dm3 G
Setting up the equation:
24.60 / 25.00 = x / 0.1
Solving for x:
x = (24.60 / 25.00) * 0.1
Therefore, the concentration of F is 0.0984 mol/dm3.
(iii) Molar mass of acid H2X:
Given that 100 cm3 of solution F contained 0.495g of acid, we can calculate the molar mass of acid H2X.
1. Calculate the number of moles of acid:
- Moles of acid = mass of acid / molar mass of acid
= 0.495g / (H:1.00 + O:6.00)
= 0.495g / 7.00g/mol
= 0.0707 mol
2. Since H2X is dibasic, the molar ratio of H2X to NaOH is 1:2. This means that 1 mole of H2X will react with 2 moles of NaOH.
As we found earlier that 1 mole of NaOH is present in 0.1 mol/L of G, we can calculate:
- Moles of H2X = (0.0707 mol * 2) / 0.1 mol/dm3 of G
3. Calculate the molar mass:
- Molar mass of H2X = mass of H2X / moles of H2X
= 0.495g / ((0.0707 mol * 2) / 0.1 mol/dm3 of G)
Plug in the values to find the molar mass of H2X.
Please note: The given information about the elements (H, O, Na) is not required to find the molar mass of acid H2X since they are given in a different context and are not directly involved in the calculation.
I hope this explanation helps! Let me know if you have any further questions.
You made a typo. O is 16 not 6.
i) concn G is 0.1 mol/dm3. Calculated as follows:
mols NaOH = g/molar mass = 0.1/40 = 0.025
M NaOH = 0.025/0.25 = 0.1 mol/dm3
ii)Note: 1 L = 1 dm3 and M = mols/dm3
2NaOH + H2X ==> Na2X + 2H2O
mols NaOH used = M x L = 0.1M x 0.025 = 0.0025
mols H2X (F) = 1/2 x 0.0025 = 0.00125
M F = mols/L = 0.00125/0.0246 = 0.051M = 0.051 mol/dm3 but you may want the answer more accurate than that.
iii)
mols H2X in 100 cc = M x L = 0.051 x 0.1 = 0.0051
mols = grams/molar mass or
molar mass = grams/mols = 0.495/0.00508 = ?