5. (2y – 1)(4y – 3) (1 point)
–2y + 3
8y^2 – 10y – 3
8y^2 – 10y + 3
8y^2 – 2y + 3
i did the rest (#1 and #3) but im stuck on #5, can u help Damon?
thanx
its c
if c is
8y^2 - 10y + 3 , then yes.
Of course! I'd be happy to help you with question #5.
To find the product of two binomials, we'll use the FOIL method. The FOIL method stands for First, Outer, Inner, Last and helps us multiply two binomials.
The given expression is (2y – 1)(4y – 3).
1. **First:** Multiply the first terms of both binomials.
(2y)(4y) = 8y^2
2. **Outer:** Multiply the outer terms of the binomials.
(2y)(-3) = -6y
3. **Inner:** Multiply the inner terms of the binomials.
(-1)(4y) = -4y
4. **Last:** Multiply the last terms of both binomials.
(-1)(-3) = 3
Now, we will combine these terms:
8y^2 - 6y - 4y + 3
The middle terms, -6y and -4y, can be combined:
8y^2 - 10y + 3
So, the correct answer for #5 is 8y^2 - 10y + 3.
Let me know if there's anything else I can assist you with!
Of course! I'd be happy to help you with the problem.
To find the product of (2y – 1) and (4y – 3), we can use the distributive property. This property allows us to multiply each term in the first expression by each term in the second expression.
So, let's distribute the first term (2y) of the first expression to both terms in the second expression:
(2y) * (4y – 3) = 8y^2 – 6y
Next, let's distribute the second term (-1) of the first expression to both terms in the second expression:
(-1) * (4y – 3) = -4y + 3
Now that we have both of these parts, we can combine them to find the final result:
(2y – 1)(4y – 3) = (8y^2 – 6y) + (-4y + 3) = 8y^2 – 10y + 3
So the correct answer for #5 is 8y^2 – 10y + 3.