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chemistry

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Radioactive decay is a process that follows first-order kinetics. The half-life of 32P is 0.03920 years; how long (in minutes) would it take for the amount of 32P to decrease to 53.25% of its initial amount?

I don't understand at all what to do here

  • chemistry -

    Use the following formula:

    T1/2 = T*ln(2)/ln(Ao/At)

    Where

    T1/2=0.03920 years
    T=?
    Ao=100%
    and
    At=53.25%

    Solve for T:

    (T1/2)/[[ln(2)/ln(Ao/At)]= To

    To=(0.03920)/[ln(2)/ln(100/53.25)]


    Answer contains four significant figures.

  • chemistry-Additional Steps -

    The answer that is given to you will be in years.


    Take To and do the following with it:

    To*(365 days/1 year)*(24hrs/1 day)*(60mins/1 Hr)= answer in minutes.

    Remember, no more than four significant figures.

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