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Assume you poured 5.00 g of KOH in 250 mL of pure water. What is the molarity of the solution you made?

  • chemistry -

    1 mole of KOH=56.11g



    Solve for moles:

    5.00g*(1 mole/56.11g)= moles of KOH

    Molarity=moles/volume (L)

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