A 0.45kgkg mass oscillates in simple harmonic motion on a spring with a spring constant of 160N/mN/m .What is the period of the oscillation?
To find the period of oscillation, we can use the formula:
T = 2π√(m/k)
where T is the period, m is the mass, and k is the spring constant.
Given:
m = 0.45 kg (mass)
k = 160 N/m (spring constant)
Substituting these values into the formula, we get:
T = 2π√(0.45/160)
First, divide the mass (0.45 kg) by the spring constant (160 N/m):
T = 2π√(0.0028125)
Next, take the square root of the result:
T = 2π * 0.053042
Finally, multiply the result by 2π to find the period:
T ≈ 0.334 seconds
So, the period of the oscillation is approximately 0.334 seconds.