Math
posted by dddd47906 .
Okay now. New question. Find the number of (m) ways in which 6 people can ride a toboggan if ONE OUT OF THREE people must drive.
M=?
PLEASE DO NOT SOLVE! Just tell me how to do the problem. You MIGHT use factorial.

If you mean that the 6person team must contain 3 drivers, then
the driver can be selected in 3 different ways
The remaining 5 riders can be arranged in P(5) = 5! ways
If I have misread the problem, please clarify. 
I think you kind of misread it.
I meant that there was ONE driver, although you pick 1 driver out of THREE drivers. Thank you for your time though. 
Can anyone answer my question?

If you read carefully, I think you will find I did. 3 ways to choose the driver,
5! ways to arrange the riders. 
thank you for your help!

there are six people and on the selected 3, 1 must be a driver. so out of the three selected, there are three wasmys to select 1 driver. we minus 1 from the six people then we be left by 5...5!.
the answer is: 3×5!= 360 ways 
there are six people and on the selected 3, 1 must be a driver. so out of the three selected, there are three ways to select 1 driver. we minus 1 from the six people then we be left by 5...5!.
the answer is: 3×5!= 360 ways