math  6th grade
posted by Skylar .
HELP! How do I solve for x:
4x+2=3x+9

subtract 3x+2 from both sides and you have
4x+2 3x2 = 3x+9 3x2
x = 7 
4x+2=3x+9
Subtract 2 from both sides of the equation.
4x = 3x + 7
Subtract 3x from both sides
x = 7 
4x+2=3x+9
Move 3x to the other side so it will become 3x ( 4x3x) same with the constant number ( 92) . Just combine the constant and the number that has coefficient.
Solution: 4x+2= 3x+9
4x3x=92
X=7