# chemistry

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0.50 mol of Fe react with 0.60 mol of O2, how many moles of Fe2O3 will form?

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4Fe + 3O2 ==> 2Fe2O3
0.50 mol Fe x (2 mol Fe2O3/4 mol Fe) = 0.50 mol Fe x (2/4) = ? mol Fe2O3.

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