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2NaOH + CuSO4 = Na2SO4 + Cu(OH)2

100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M NaOH and 0.5M CuSO4 must be used in mL?

Any help would be awesome- even a formula on how to solve

  • Chemistry -

    Two stoichiometry problems; one for Cu(OH)2 to CuSO4 and one for Cu(OH)2 to NaOH. Stoichiometry problems, for the most part, are worked the same way.
    Step 1. Convert what you have (100 g Cu(OH)2 to mols. mols = grams/molar mass = ?

    Step 2. Convert mols Cu(OH)2 to mols NaOH. You can tell from the coefficients in the balanced equation, that mols NaOH = twice the mols Cu(OH)2.

    Step 3. Convert mols NaOH to grams. g = mols x molar mass. Assuming 100% yield that is g NaOH needed to produce 100 g of the product you want.

    Do the same thing for converting 100 g Cu(OH)2 to g CuSO4.

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