posted by Anonymous .
How many grams of Li2O must be carried on board to remove 85.0kg of water?
Li2O + HOH ==> 2LiOH
mols H2O = 85,000/18 = estimated 4722
Now convert mols H2O to mols Li2O using the coefficients in the balanced equation. That's estimated 4722 x (1 mol Li2O/1 mol H2O) = about 4722 mols Li2O.
Now convert that to g Li2O. g = mols x molar mass.
Go back and confirm my estimates.