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if .5 mole of baCl2 is mixed with .2 mole of Na3Po4.Then maximum number of mole of Ba3(PO4)2 is

  • chemistry -

    3Ba^2+ + 2PO4^3- ==> Ba3(PO4)2(s)

    Convert mols each to mols product.
    0.5 mol BaCl2 x (1 mol product/3 Ba^2+) = approx0.167 mols Ba3(PO4)2 produced.

    0.2 mol Na3PO4 x (1 mol product/2 mol PO4^3-) = 0.1 mol Ba3(PO3)2 produced.
    In limiting reagent problems the smaller number ALWAYS wins. Therefore, the max number of Ba3(PO4)2 that can be produced is 0.1 mol.

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