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The high temperature X (in degrees Fahrenheit) on January days in Columbus, Ohio varies according to the Normal distribution with mean 21 and standard deviation 10.

The value of P(X < 10) is

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http://davidmlane.com/hyperstat/z_table.html

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I added the mean of 21 and SD of 10 and the probability is 0.9715. That is not one of my options, please help!

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These are my options.
A.0.30
B.0.40
C.0.60
D.0.90

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Well, it must be immediately obvious that .9715 is bogus. A score of 10 is more than a whole SD below the mean, so there is no way that P(x<10) > 1/2

When I plugged in the data, I got P(x<10) = 0.1357

Still not one of your choices. However, the closest is 0.3, since you know that the score is well below the mean.

There's a typo somewhere in the problem or the answers.

I get
.30 = P(x<15 or x>26)
...
.90 = P(x<33 or x>8)

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