Help please
A 200.0 g copper block absorbs 2.34 × 10^3 J of heat to raise its temperature by 30.0 K. What is the specific heat of copper?
nvm, i think my above answer is wrong i got another answer .39 J/g*k is this right???
2,340 / 0.20 / 50.0 =
i got 234 as an answer??
is it right?
To find the specific heat of copper, you can use the formula:
Q = mcΔT
Where:
Q is the heat absorbed or released by the object
m is the mass of the object
c is the specific heat capacity of the material
ΔT is the change in temperature
In this case, the question tells you that a copper block with a mass of 200.0 g absorbs 2.34 × 10^3 J of heat and the temperature changes by 30.0 K.
So, let's substitute the given values into the formula:
Q = mcΔT
2.34 × 10^3 J = (200.0 g) × c × (30.0 K)
Now, we can rearrange the equation to solve for the specific heat capacity (c):
c = Q / (mΔT)
Substituting the values we have:
c = (2.34 × 10^3 J) / (200.0 g × 30.0 K)
Calculating the specific heat capacity:
c = 0.039 J/(g·K)
Therefore, the specific heat of copper is 0.039 J/(g·K).