Math - PreCalc (12th Grade)

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What is the value of this expression when n approaches infinity?
4−(4/n)+(5/n)+(15/3n^2)

A) 20
B) 10
C) 5
D) 4
E) 1

  • Math - PreCalc (12th Grade) -

    Use you "sense" of numbers to see what happens to the fractions as n gets larger.
    (I think your last term should read 15/(3n^2) or else it becomes large as n gets large)

    e.g. look at 5/n
    suppose n = 100,000, then 5/n = .00005 , which is close to zero
    suppose n = 1,000,000,000 , then 5/n = .000000005, even closer to zero

    so as n gets really big
    4/n and 5/n each ---> 0
    and 15/(3n^2) ---> even faster

    so you are stuck with
    4 - 0 + 0 + 0 = 4

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