derivatives
posted by jnky .
x^2cosx2xsinx2cosx

I assume that you want the derivative, since you titles your post that way.
if y = x^2cosx2xsinx2cosx
dy/dx = (x^2)(sinx) + 2x cosx  2x(cosx)  2sinx + 2sinx
= x^2( sinx) + 4x( cosx)
etc if needed 
d/dx sinx = cosx

yup!
sloppiness on my part
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