Trigonometry
posted by Joey .
Mountain officials want to build a new ski lift from B to C as shown in the figure below. The distance from A to C is 1480 feet. They measure angle DAC to be 32 degrees and angle DBC to be 18 degrees. What is the distance A from to B? Round your answer to the nearest tenth of a foot.

no diagram. Better explain a bit more, the relative positions of A,B,C,D

hyptotenuse AC= 1480
opposite CD= 784.28056
adjacent AD 914.7554 
figures above are correct not sure why it has me listed as Stephen. Also, hypotenuse of CB is 2537.98496522845. they are two attached triangles. CAB is the outermost triangle. CD is the opposite side of both triangles. CAD with the angle of 32 degrees. CAD has a hypotenuse of 1480.

Looks like its a triangle within a triangle problem. Still researching to try to find out how to solve
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