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Using a table of standard electrode potentials (as in Appendix M of your text), calculate the standard cell potential, Eo, for: 2 Fe2+(aq) + Cl2(g) 2 Fe3+(aq) + 2 Cl(aq).

Anode: 2 Fe2+ 2 Fe3+ + 2 e
Eox = 0.771 V
Cathode: Cl2 + 2 e 2 Cl Ered = +1.36 V
Enet = +0.59 V

I think Eox = -0.771 and
Ered = +1.36
Then 1.36 + (-0.771) = ?
Your answer is right; I don't agree with what you called Eox. The anode is oxidized, yes, and that is an oxidation, yes. But the potential for that electrode is -0.771. The reduction potential is 0.771; the oxidn potential is -0.771.

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