which of the following compound contain more than 10 atoms per formula: a)ammonium phosphate, b) aluminium carbonate, C)iron(III) cyanide,
ammonium phosphate is (NH4)3PO4
I see 20 atoms per molecule.
aluminum carbonate is Al2(CO3)3
I see 14 atoms per molecule.
iron cyanide is Fe3CN.
I see 5 atoms per molecule
To determine which compound contains more than 10 atoms per formula, we need to calculate the number of atoms in each compound and compare the results.
a) Ammonium phosphate: The formula for ammonium phosphate is (NH4)3PO4. Let's break it down:
- (NH4): Ammonium consists of one nitrogen (N) and four hydrogen (H) atoms. So, there are 5 atoms in total.
- PO4: Phosphate consists of one phosphorus (P) and four oxygen (O) atoms. So, there are 5 atoms in total.
Adding the atoms from (NH4) and PO4, we get a total of 10 atoms in ammonium phosphate.
b) Aluminium carbonate: The formula for aluminium carbonate is Al2(CO3)3. Let's break it down:
- Al2: Aluminum consists of two aluminum (Al) atoms. So, there are 2 atoms in total.
- (CO3)3: Carbonate consists of one carbon (C) and three oxygen (O) atoms. So, there are 4 atoms in total per carbonate group. Since there are three carbonate groups, we multiply 4 atoms by 3 to get a total of 12 atoms.
Adding the atoms from Al2 and (CO3)3, we get a total of 14 atoms in aluminium carbonate.
c) Iron(III) cyanide: The formula for iron(III) cyanide is Fe(CN)3. Let's break it down:
- Fe: Iron consists of one iron (Fe) atom. So, there is 1 atom in total.
- (CN)3: Cyanide consists of one carbon (C) and one nitrogen (N) atom. So, there are 2 atoms in total per cyanide group. Since there are three cyanide groups, we multiply 2 atoms by 3 to get a total of 6 atoms.
Adding the atoms from Fe and (CN)3, we get a total of 7 atoms in iron(III) cyanide.
Comparing the results, we see that aluminium carbonate (Al2(CO3)3) contains more than 10 atoms per formula, and therefore is the compound that meets the given criteria.