Calculus

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Solve the initial-value problem.
y'' - 2y' + y = 0 , y(2) = 0 , y'(2) = 1

  • Calculus -

    y = e^x (c1 + c2*x)
    y' = e^x (c1 + c2 + c2*x)

    Now plug in the initial conditions to get

    e^2 (c1 + 2c2) = 0
    e^2 (c1 + c2 + 2c2) = 1
    Now just solve for c1 and c2

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