Calculus
posted by Sandy .
Solve the initialvalue problem.
y''  2y' + y = 0 , y(2) = 0 , y'(2) = 1

y = e^x (c1 + c2*x)
y' = e^x (c1 + c2 + c2*x)
Now plug in the initial conditions to get
e^2 (c1 + 2c2) = 0
e^2 (c1 + c2 + 2c2) = 1
Now just solve for c1 and c2
Respond to this Question
Similar Questions

calculus
How do you solve the initial value problem? 
Calculus
Solve the following initial value problem explicitly: y'= ye^x , y(0)=1 How do you solve this problem? 
calculus
solve the initial value problem by separation of variables 8. dy/dx=x+1/xy, x>0, y(1)=4 
calculus
solve the initial value problem by separation of variables dy/dx=x^2y^2, y(4)=4 
calculus
solve the initial value problem by separation of variables dy/dx=xy^2, y(1)=0.25 
calculus
solve the initial value problem by separation of variables dy/dx=xy^2, y(1)=0.25 
calculus
solve the initial value problem by separation of variables dy/dx=x^2y^2, y(4)=4 
calculus
how do you solve the initial value problem by separation of variables dy/dx=x^2y^2, y(4)=4 
Calculus
Solve the initial value problem. dy/dx = 3 sinx and y = 2 when x = 0. Is this c = 5? 
Calculus
Solve the initial value problem. 7x^63x^2+5 and u = 1 when x = 1. Is this x^7  x^3 + 5x  4?