In 1901, Thomas Edison invented the nickel-iron battery. The follwing reaction takes place in the battery.
Fe(s) + 2 NiO(OH)(s) + 2 H2O(l) Fe(OH)2(s) + 2 Ni(OH)2(aq)
How many mole of Fe(OH)2, is produced when 3.70 mol Fe and 6.95 mol NiO(OH) react?
To determine the number of moles of Fe(OH)2 produced, we need to compare the stoichiometric coefficients of Fe and Fe(OH)2 in the balanced chemical equation.
The balanced chemical equation is:
Fe(s) + 2 NiO(OH)(s) + 2 H2O(l) → Fe(OH)2(s) + 2 Ni(OH)2(aq)
From the equation, we can see that 1 mole of Fe reacts to produce 1 mole of Fe(OH)2.
So, if 3.70 moles of Fe reacts, it will produce 3.70 moles of Fe(OH)2.
Therefore, when 3.70 moles of Fe and 6.95 moles of NiO(OH) react, the number of moles of Fe(OH)2 produced will be 3.70 moles.
To determine the number of moles of Fe(OH)2 produced when 3.70 mol Fe and 6.95 mol NiO(OH) react, we need to first balance the equation.
The balanced equation is:
Fe(s) + 2 NiO(OH)(s) + 2 H2O(l) -> Fe(OH)2(s) + 2 Ni(OH)2(aq)
From the balanced equation, we can see that the molar ratio between Fe(OH)2 and Fe is 1:1. This means that for every 1 mole of Fe, 1 mole of Fe(OH)2 will be produced.
Similarly, the molar ratio between Fe(OH)2 and NiO(OH) is also 1:1. This means that for every 1 mole of NiO(OH), 1 mole of Fe(OH)2 will be produced.
Now we can calculate the number of moles of Fe(OH)2 produced when 3.70 mol Fe and 6.95 mol NiO(OH) react.
Since the molar ratio between Fe(OH)2 and both Fe and NiO(OH) is 1:1, the number of moles of Fe(OH)2 produced will be equal to the smaller of the number of moles of Fe and NiO(OH).
In this case, since we have 3.70 mol of Fe and 6.95 mol of NiO(OH), the smaller number is 3.70 mol.
Therefore, when 3.70 mol Fe and 6.95 mol NiO(OH) react, the number of moles of Fe(OH)2 produced is 3.70 mol.
You need to find the arrow key on your computer and use it. --> or ==> or >>>>.
Using the coefficients in the balanced equation, convert mols each to mols Fe(OH)2.
3.70 mols Fe x (1 mol Fe(OH)2/1 mol Fe) = 3.70 mols Fe.
6.95 mol NiO(OH)2 x (1 mol Fe(OH)2/2 mol NiO(OH)2) = 3.475.
You get two different values which mans one of them is not right. In limiting reagent problems the smaller number ALWAYS wins.