college chem
posted by hershi
Determine the rate of consumption of I− if the initial concentration of IO3− was 0.6634 M and decreased to 0.5745 M after 0.3964 hours. Use the reaction below.
IO3− + 5I− + 6H+ ↔ 3I2 + 3H2O

DrBob222
0.66340.5745 = 0.0889 M in 0.3964 hrs = about 0.22 M/hr (but you may want to change that to M/s.
Then rate change IO3^ x (5 mol I/1 mol IO3) = ? rate change for I^
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