The measures of the sides of a triangle are shown as polynomials. The measures are: 2s^3 + 4; 5s; 4s^2 + 1. Write a polynomial to represent the perimeter of the triangle.
Isn't the formula for a triangle A=1/2bh? Do we use the formula for this question or-
To find the perimeter of a triangle, we need to add up the lengths of all three sides.
The measures of the sides of the triangle are: 2s^3 + 4, 5s, and 4s^2 + 1.
Therefore, the polynomial to represent the perimeter would be:
(2s^3 + 4) + (5s) + (4s^2 + 1)
Simplifying, we get:
2s^3 + 4 + 5s + 4s^2 + 1
Combining like terms, the polynomial that represents the perimeter of the triangle is:
2s^3 + 4s^2 + 5s + 5
To find the perimeter of the triangle, we need to add up the lengths of all three sides. The side lengths are given as polynomials:
Side 1: 2s^3 + 4
Side 2: 5s
Side 3: 4s^2 + 1
To find the perimeter, we add up these three polynomials:
Perimeter = (2s^3 + 4) + (5s) + (4s^2 + 1)
To simplify this expression, we can combine like terms:
Perimeter = 2s^3 + 4 + 5s + 4s^2 + 1
Now, let's arrange the terms in descending order of the exponent:
Perimeter = 2s^3 + 4s^2 + 5s + 4 + 1
Finally, combine the constants:
Perimeter = 2s^3 + 4s^2 + 5s + 5
Therefore, the polynomial that represents the perimeter of the triangle is 2s^3 + 4s^2 + 5s + 5.
Perimeter
= 2s^3+4 + 5s + 4s^2 + 1
= 2s^3 + 4s^2 + 5s + 5
Why was this question difficult for you?
If you are given the three sides of a triangle, wouldn't you just add them up to find the perimeter ?