Finite Math and Applied Calculus
posted by Chris .
Betty Sue sets up a retirement account. For the first 35 years, she deposits
$500 at the end of each month into an account with an annual interest rate of 3.6%, compounded monthly. Then, she stops making monthly payments and transfers the money into a different account with an annual interest rate of 4%, compounded quarterly for a period of 10 years. How much money has she saved for retirement at the end of her 45 years if saving?

first 35 years
35 * 12 = 420 months = n
r = .036/12 = .003 monthly interest rate
p= present value of sinking fund
N = deposit each period of 1 month = 500
p = N [ (1+r)^n  1 ] /r
p = 500 [ (1.003)^420  1 ] / .003
p = 419,796.33 after 35 years
now the final 10 years
quarterly for 10 years = 40 periods
interest rate = .04/4 = .01
1.01^40 = 1.48886
times 419 etc = 625,019.54