# physics

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A remote-control vehicle moves forward with constant acceleration. During the ﬁrst two seconds, it
travels 55.0(cm), and during the following two seconds, another 77.0(cm)
(a) Calculate the vehicleâ€™s initial velocity and its acceleration.
(b) What distance will it travel the next 4.0(s)?

• physics -

.55 = Vi(2) + (1/2) a 2^2

0.55 = 2 Vi + 2 a

total distance after 4 seconds = .55+.77
= 1.32 m

1.32 = 4 Vi + (1/2) a (4^2)
1.32 = 4 Vi + 8 a
--------------------
so solve these two equations for Vi and a:
1.32 = 4 Vi + 8 a
0.55 = 2 Vi + 2 a

• physics -

thank you so much Damon!

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