Calculate the formula mass for each of the following halogen compounds to five or more significant figures:?
bake asked 5 months ago
(a) NaIO3 (antiseptic)
(b) CCl2F2 (former refrigerant)
(a) NaIO3 (sodium iodate)
To calculate the formula mass, we need to determine the atomic masses of each element in the compound.
Atomic mass of Na (sodium) = 22.9898 g/mol
Atomic mass of I (iodine) = 126.9045 g/mol
Atomic mass of O (oxygen) = 15.9994 g/mol
Now, we can calculate the formula mass:
Formula mass of NaIO3 = Atomic mass of Na + Atomic mass of I + (3 x Atomic mass of O)
= 22.9898 + 126.9045 + (3 x 15.9994)
= 22.9898 + 126.9045 + 47.9982
= 197.8925 g/mol
Therefore, the formula mass of NaIO3 is approximately 197.8925 g/mol.
(b) CCl2F2 (dichlorodifluoromethane)
To calculate the formula mass, we need to determine the atomic masses of each element in the compound.
Atomic mass of C (carbon) = 12.0107 g/mol
Atomic mass of Cl (chlorine) = 35.453 g/mol
Atomic mass of F (fluorine) = 18.9984 g/mol
Now, we can calculate the formula mass:
Formula mass of CCl2F2 = Atomic mass of C + (2 x Atomic mass of Cl) + (2 x Atomic mass of F)
= 12.0107 + (2 x 35.453) + (2 x 18.9984)
= 12.0107 + 70.906 + 37.9968
= 120.9135 g/mol
Therefore, the formula mass of CCl2F2 is approximately 120.9135 g/mol.
To calculate the formula mass of a compound, we need to determine the atomic masses of the elements present in the compound and sum them up according to their respective subscripts.
(a) NaIO3:
To calculate the formula mass of NaIO3, we need to determine the atomic masses of sodium (Na), iodine (I), and oxygen (O).
The atomic mass of sodium (Na) is 22.99 g/mol.
The atomic mass of iodine (I) is 126.90 g/mol.
The atomic mass of oxygen (O) is 16.00 g/mol.
The subscripts in the formula indicate the number of each element present in the compound. In this case, we have 1 Na, 1 I, and 3 O.
Now, we can calculate the formula mass using the following equation:
Formula Mass = (Atomic mass of Na × Number of Na) + (Atomic mass of I × Number of I) + (Atomic mass of O × Number of O)
Plugging in the values we have:
Formula Mass = (22.99 g/mol × 1) + (126.90 g/mol × 1) + (16.00 g/mol × 3)
Calculating this, we get:
Formula Mass = 22.99 g/mol + 126.90 g/mol + 48.00 g/mol = 197.89 g/mol
Therefore, the formula mass for NaIO3 is approximately 197.89 g/mol.
(b) CCl2F2:
To calculate the formula mass of CCl2F2, we need to determine the atomic masses of carbon (C), chlorine (Cl), and fluorine (F).
The atomic mass of carbon (C) is 12.01 g/mol.
The atomic mass of chlorine (Cl) is 35.45 g/mol.
The atomic mass of fluorine (F) is 18.99 g/mol.
The subscripts in the formula indicate the number of each element present in the compound. In this case, we have 1 C, 2 Cl, and 2 F.
Using the formula mass equation:
Formula Mass = (Atomic mass of C × Number of C) + (Atomic mass of Cl × Number of Cl) + (Atomic mass of F × Number of F)
Plugging in the values we have:
Formula Mass = (12.01 g/mol × 1) + (35.45 g/mol × 2) + (18.99 g/mol × 2)
Calculating this, we get:
Formula Mass = 12.01 g/mol + 70.90 g/mol + 37.98 g/mol = 120.89 g/mol
Therefore, the formula mass for CCl2F2 is approximately 120.89 g/mol.