Find the force of gravity between a newborn baby (mass = 2.9kg ) and the planet Mars (mass = 6.4×1023kg), when Mars is at its closest to Earth (distance = 5.6×1010m).

To find the force of gravity between the newborn baby and Mars, we can use Newton's law of gravitation:

\( F = \frac{{G \cdot m_1 \cdot m_2}}{{r^2}} \)

where:
- F is the force of gravity
- G is the gravitational constant (\( 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \))
- \( m_1 \) and \( m_2 \) are the masses of the objects
- r is the distance between the centers of the two objects

Given:
\( m_1 = 2.9 \, \text{kg} \) (mass of the newborn baby)
\( m_2 = 6.4 \times 10^{23} \, \text{kg} \) (mass of Mars)
\( r = 5.6 \times 10^{10} \, \text{m} \) (distance between the newborn baby and Mars)

Plugging these values into the formula, we get:

\( F = \frac{{6.67 \times 10^{-11} \times 2.9 \times 6.4 \times 10^{23}}}{{(5.6 \times 10^{10})^2}} \)

\( F = \frac{{2.31376 \times 10^{13}}}{{3.136 \times 10^{21}}} \)

\( F = 7.38 \times 10^{-9} \, \text{N} \)

Therefore, the force of gravity between the newborn baby and Mars, when Mars is at its closest to Earth, is approximately \( 7.38 \times 10^{-9} \, \text{N} \).

To find the force of gravity between the newborn baby and the planet Mars, we can use Newton's law of universal gravitation:

F = (G * m1 * m2) / r^2

where:
F is the force of gravity
G is the gravitational constant (approximately 6.67430 × 10^-11 Nm^2/kg^2)
m1 is the mass of the newborn baby (2.9kg)
m2 is the mass of Mars (6.4×10^23 kg)
r is the distance between the two objects (5.6×10^10m)

Substituting the values into the formula:
F = (6.67430 × 10^-11 Nm^2/kg^2 * 2.9kg * 6.4×10^23 kg) / (5.6×10^10m)^2

First, we need to calculate the denominator:
(5.6×10^10m)^2 = (5.6 × 10^10m) * (5.6 × 10^10m)
= 3.136 × 10^21 m^2

Now let's calculate the numerator:
6.67430 × 10^-11 Nm^2/kg^2 * 2.9kg * 6.4×10^23 kg
≈ (2.192 × 10^13 Nm^2/kg^2) * (6.4×10^23 kg)
= 1.403 × 10^37 Nm^2/kg

Finally, let's calculate the force of gravity:
F = (1.403 × 10^37 Nm^2/kg) / (3.136 × 10^21 m^2)
≈ 4.47 × 10^15 N

Therefore, the force of gravity between the newborn baby and Mars, when Mars is at its closest to Earth, is approximately 4.47 × 10^15 N.