Physics
posted by Barb .
Problem 1 (80 points) Consider a spring of equilibrium length L, lying horizontally
in a frictionless trough. The spring has cross sectional area S perpendicular to
its length. The trough constrains the motion of the spring so that any wave
propagating along the spring is a longitudinal wave. Here, our goal is to nd
the wave equation for such a longitudinal wave. The spring constant for this
spring is k. The spring has a uniform linear mass density, , in equilibrium:
= M/L, where M is the total mass of the spring.
To describe this longitudinal wave, we can start by doing a Newtonian
mechanics calculation1
. Key variables to pay attention to are x and D: x
is the position of the points of the spring in equilibrium, and D(x; t) is the
displacement of each such point relative to its xed equilibrium position, x. So,
x is not the position of the \particle" (de ned rigorously in the next paragraph)
in the presence of wave, but just an \index" for each particle, as in all wave
descriptions; the position is given by x + D(x; t), where x is tindependent.
Consider a very small positive value of x such that x = L/N where
N is a large positive integer. We can consider that the spring is divided into
small segments of equal length x in equilibrium. Each segment is what we
can treat as a \particle" within Newtonian mechanics. For this reason, we shall
call each segment a \particle spring." Let us de ne x as the position of the
left end of a particle spring. Each particle spring is elongated or compressed
as wave propagates, and such elongation or compression results in nite values
of D(x; t) (displacement at left end) and D(x + x; t) (displacement at right
end). It is important to note that within each particle spring, the spring is
not uniformly compressed or elongated, in general, and Hooke's law cannot be
applied to such a nonuniformly deformed spring as a whole.
Because of the last property, we must divide each particle spring of ours
further into many littler springs! For this, we take " = x/N2. Here, N2 is a
large enough positive integer so that each littler spring of equilibrium length ",
which we can call a \nano spring," can be considered as uniformly compressed
or elongated, always. Therefore, in general, when wave propagates, we can
apply Hooke's law for, and only for, each nano spring.
Mathematically, either x or " is equivalent to \the in nitesimal" in
dierential calculus. Note that, in this problem, k is used for the spring constant
of the entire spring, and is not used for wave number.
(a) Find the spring constant of each particle spring (kp) in terms of k and
N. [Hint: This is a spring in series problem, discussed in class. Consider a
situation where the length of the spring changes, L → L + L, uniformly, and
1While this calculation has an essential similarity to that for a sound wave described in Section
5.3, you do not need to understand that section to do this problem.
consider Newton's third law and Hooke's law (which is applicable if the spring
is uniformly compressed or elongated, not carrying a wave).]
(b) Find the spring constant of each nano spring (knano), in terms of k, N, and N2.
(c) Consider a nano spring whose left end is at x and whose right end is at x + " in
equilibrium. D(x; t) and D(x + "; t) cause a nite spring force exerted by this
spring. Prove that the spring force exerted by this nano spring at left end is
proportional to @D
@x , and nd the proportionality constant in terms of k and L.
(d) Now consider a nano spring whose left end is at x+x−" and whose right end is
at x+x in equilibrium. Prove that the spring force exerted by this nano spring
at right end is proportional to @D
@x ∣
x+x
, and nd the proportionality constant
in terms of k and L.
(e) From the answers of the previous two parts and Newton's third law, it is now
possible to calculate the net force acting on the particle spring at index x, and
use Newton's second law to set up the equation of motion for the particle. Find
the equation of motion. Your answer must involve the following symbols only:
D; t; x; ; k; L.
(f) Comparing the equation of motion that you obtained in the previous part with
Eq. 5.1, identify the wave speed in this case. Check the physical dimension of
your answer.
(g) Young's modulus is de ned as Y =
F/S
∣L∣/L
, where F = k∣L∣ is the applied force,
and L is the spring contraction or elongation. Find Y in terms of k; L; and S.
(h) Express the speed of wave in terms of Y and , where is the volume mass
density = /S. Compare your answer with Eq. 4.21.
Problem 2 (40 points) A string with mass M and length L is hanging from the
ceiling.
(a) The string is at rest. Let us de ne the coordinate from top to bottom as
x (x = 0 at top and x = L at bottom). Find the tension in the string as a
function of x;M; L; and g.
(b) Consider a transverse string wave generated on this string. Show that the
speed of the wave, v, is x dependent and nd v as a function of x;M; L;
and g (some of these symbols may not appear in the answer).
(c) You push the bottom end of the string (lightly) in the horizontal direction.
Assuming that there is no loss of energy (no damping). Will the wave
propagate all the way to the top? Explain your answer brie
y.
(d) You disturb the string very near the top, by pushing the very near top
part horizontally. Again, assume no damping. How long will it take for
this disturbance to reach the bottom of the string? Your answer must be
expressed as a function of L; g; and M (some of these symbols may not
appear in the answer).
Page 2 (total number of pages: 2)
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