MATH
posted by Anonymous .
I still don't know how to completely solve systems by substitution. Can someone please help me?
1. Y=11+x
3x+10y=6
How would you know where to plug in the right section of the equation in a certain place?
2. Y =6x5
Y =x+9

MATH 
Steve
substitute the value of a variable from one equation into the other equation. For #1, we are told
y = x11
So, substitute that into the other equation, and we have
3x + 10(x11) = 6
3x + 10x  110 = 6
13x = 104
x = 8
So, y = x11 = 3
Be sure to check the solution to make sure it satisfies both original equations.
Now do #2 in just the same way. 
MATH 
Anonymous
Okay! On #2 how would you set it up since there's no equal signs
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