Can someone please check my math Hw? Thank you!!

Solve each system by elimination.

1. 8x+7y=-1
-9x-7y=2
I got (-1,1)
2. 4x+3y=1
-4x-7y=-13
I got (2,-2)
3. -7x-6y=-21
-x-6y=-3
I got (3,0)
4. -2x+3y=-16
-2x-5y=-16
I got (8,0)
5. -7x+2y=13
-14x+4=26
I got (0,0)
6. 15x-8y=14
-5x+9y=8
I got (2,2)
7. x-6y=22
-2x+3y=1
I got (-8,-5)
8. 2x+10y=30
-10x-6y=-18
I got (0,3)
9. -35x-15y=0
56x+24y=0
I got (0,0)
10. -56x+72y=-16
-49x+63y=-14
I need help with this one!!!

You do not need us to check.

Put your answers back in the original equations.
as for #10
-56x+72y=-16
-49x+63y=-14

divide top by 2
divide second by 7
-7 x + 9 y = -2
-7 x + 9 y = -2
NO solution. This is the same line repeated, no intersection
In linear algebra if one row is identical to or a multiple of another, the determinant of the coefficient matrix is zero and the solution is undefined.

Can you check number 5? Is it no solution?

To solve the given system of equations:

1. 8x + 7y = -1
-9x - 7y = 2

To eliminate the variable "y," you can add the two equations together:
(8x + 7y) + (-9x - 7y) = (-1) + 2

This simplifies to:
8x - 9x + 7y - 7y = 1

Combining similar terms, we get:
-x = 1

To solve for "x," you can multiply both sides of the equation by -1:
(-1)(-x) = (-1)(1)

This gives us:
x = -1

Now that we have the value of "x," substitute it back into one of the original equations (let's use the first one) to solve for "y":
8(-1) + 7y = -1

Simplifying further:
-8 + 7y = -1

Add 8 to both sides:
-8 + 8 + 7y = -1 + 8

This simplifies to:
7y = 7

Divide both sides by 7:
(7y) / 7 = 7 / 7

This gives us:
y = 1

Therefore, the solution to the first system of equations is (x, y) = (-1, 1).

You can apply similar steps to solve the remaining systems of equations.