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A) A hot air balloon has just lifted off and is rising at the constant rate of 1.70 m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 10.4 m/s. If the passenger is 3.00 m above her friend when the camera is tossed, how much time does it take for the camera to reach her?
B)How high is the passenger when the camera reaches her?

  • physics -

    camera:
    Vi = 10.4

    v = Vi - g t

    h = 10.4 t - 4.9 t^2

    passenger:
    v = 1.7
    h = 3 + 1.7 t

    when are the two heights the same?

    3 + 1.7 t = 10.4 t - 4.9 t^2
    solve quadratic for t

    then use h = 3 + 1.7 t to get height

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