Algebra Check
posted by Anonymous .
What is the simplified form of 3a^4b^2c^3?
a. (81a^4c^3)/(b^2)
b. (81a^4)/(b^2c^3)
c. (3a^4)/(b^2c^3)
d. (3a^4c^3)/(b^2)
D
What is a^2 if a = 5?
a. 25
b. 25
c. 1/25
d. 1/25
D
What is (m)^3n if m = 2 and n = 24?
a. 3
b. 3
c. 4
d. 4
A

What is the simplified form of 3a^4b^2c^3?
a. (81a^4c^3)/(b^2)
b. (81a^4)/(b^2c^3)
c. (3a^4)/(b^2c^3)
d. (3a^4c^3)/(b^2)
D YES
What is a^2 if a = 5?
a. 25
b. 25
c. 1/25
d. 1/25
D No 1/(5)^2 = 1/25 so C
What is (m)^3n if m = 2 and n = 24?
a. 3
b. 3
c. 4
d. 4
A NONE OF THESE. 2^72 is huge. You have a TYPO 
It is not 3n. It is (m)^3 n. So it would be .125* 24, which is how I did it.

[(m)^3 ] n
[1/(2)^3] (24)
(1/8)(24)
3
YES A 
Thank you so much! Just one quick question...is it a rule to always simplify first and then substitute, as in question 2?

That is up to you.

Are all of these correct Damon?

all of Damon's answers are correct
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