physics (Urgent)!!!!!!!!!!!!!!!!!!!!!!
posted by Anonimus .
A gunman standing on a sloping ground fires up the slope. The initial speed of the bullet is v0= 340 m/s. The slope has an angle α= 12 degrees from the horizontal, and the gun points at an angle θ from the horizontal. The gravitational acceleration is g=10 m/s2.
(a) For what value of θ ( where θ>α) does the gun have a maximal range along the slope? (in degrees, from the horizontal)
θ=
unanswered
(b) What is the maximal range of the gun, lmax, along the slope? (in meters)
lmax=

a) 45+a/2=51 degrees
b)(1−sin)*v0^2/(g*cos^2(á)) 
@Greco b one more time

Lordy me, and I did this one by mistake yesterday not knowing it was an 8:01 final question

(v_0^2*(1sin(alpha))/(g*cos^2(alpha))
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