Math
posted by Celeste .
the area of a rectangle is 65yd^2 the length is 3yd less than double the width. Find the dimensions

L = (2 W  3)
L * W = 65
(2 W  3) W = 65
2 W^2  3 W  65 = 0
( 2 W  13) ( W + 5) = 0
5 will just not do so W = 13/2 = 6.5
then L = 10
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