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the area of a rectangle is 65yd^2 the length is 3yd less than double the width. Find the dimensions

  • Math -

    L = (2 W - 3)

    L * W = 65
    (2 W - 3) W = 65

    2 W^2 - 3 W - 65 = 0

    ( 2 W - 13) ( W + 5) = 0

    -5 will just not do so W = 13/2 = 6.5
    then L = 10

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