Calculus

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what is the limit n to infinite of
cos1*cos(1/2)*cos(1/4)*cos(1/8)*cos(1/16)*...*cos(1/2^n)

  • Calculus -

    Since sinc(1) = cos(1/2)*cos(1/4)*cos(1/8)*cos(1/16)*...*cos(1/2^n)

    the limit here is cos(1)sinc(1) = cos(1)sin(1) = 0.4546...

    You can read about sinc(x) in various places. This function doesn't usually pop up in introductory calculus courses.

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