# Algebra 2

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How do you solve this exponential equation using logarithms?

2*5^x=85

Do you start like this?

xlog2*5=log85

I don't know what to do after that.

• Algebra 2 -

I think I figured it out.
85/2=42.5

log5=log42.5

log42.5/log5

=2.330 to the third decimal

• Algebra 2 -

2^5x = 85
Log2^5x = log85
5xlog2 = log85
Solve for x
x = log85/5log2

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