geometry
posted by ajhane .
in circle O, perpendicular chords AB and CD intersect at E so that AE=2, eb=12 and CE=4. find the radius of a circle O and the shortest distance from e to the circle

The two chords intersect to form 2 similar triangles, in this case 2 similar rightangled triangles
so we can easily find that ED = 24
by Pythagoras:
AC = √20
and BD = 6√20
Does that give you a start ?
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