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geometry

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in circle O, perpendicular chords AB and CD intersect at E so that AE=2, eb=12 and CE=4. find the radius of a circle O and the shortest distance from e to the circle

  • geometry -

    The two chords intersect to form 2 similar triangles, in this case 2 similar right-angled triangles
    so we can easily find that ED = 24

    by Pythagoras:
    AC = √20
    and BD = 6√20

    Does that give you a start ?

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