find the linear transformation model of log y^ = 0.6021x + 0.4771.
Log y^ = 0.6021x + 0.4771 )
y=10^(0.6021x)*10^( 0.4771 )
y=3*4^x
Thanks that is what I had
To find the linear transformation model of log y^ = 0.6021x + 0.4771, we need to convert it to its exponential form.
The exponential form of a logarithmic equation is given by y = e^(mx + c), where e is the base of the natural logarithm (approximately 2.718), m is the coefficient of x, and c is the constant term.
So, we can rewrite the given equation log y^ = 0.6021x + 0.4771 as y^ = e^(0.6021x + 0.4771).
Let's simplify it further:
y^ = e^0.6021 * e^0.4771
Now, we have obtained the linear transformation model in its exponential form:
y^ = ke^(0.6021x),
where k = e^0.4771.