# Calculus

posted by tiffany

Find the area of the indicated region. We suggest you graph the curves to check whether one is above the other or whether they cross, and that you use technology to check your answer.

Enclosed by y = x^2 − 4x + 1 and y = −x^2 + 4x − 5

1. Steve

the curves intersect at x=1,3 so the area is

∫[1,3] (−x^2 + 4x − 5 )-(x^2 − 4x + 1) dx
= ∫[1,3] -2x^2 + 8x - 6 dx
= -2/3 x^3 + 4x^2 - 6x [1,3]
= 8/3

2. tiffany

thank you so much

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