math
posted by Matthew .
Ellis plans to hand out door prizes as the guest arrive she has 256 guests every 6th guest will receive a mug and for every 14 guests will receive a t shirt. Which guest will be the first to receive both mug and at shirt? Next question is elli has 8 and 1/2 pound bags of mints. She plans to put 1/12 pound at each place setting. will she have enough mints? PLEASE HELP I TRIED so hard and I can't get the answer thank you so much I need help with the answer before tomorrow morning!!!!!!!!!

LCM(6,14) = 42, so the 42nd guest will receive both.
For the mints, 256 guests at 1/12 lb/guest shows she needs
256/12 = 21.33 lbs of mints
8 1/2 lbs only serves 102 guests (8*12 + 6) 
For the first one:
if you have to, just list em all out
Mugs: 6,12,18,24,30,36,42,48,54,60....
Shirts: 14,28,42,56,70....
See any numbers in common so far? Yep: the 42. So the 42nd guest will get both
Second one: Can't figure it out, cuz not enough information, did you leave something out, like how many place settings there are? 
Yeah what Steve said

No she won't have enough

I agree with sam

You have to find the LCM=Least Common Multiple.
So if your prime factorize 6 and 14 you will get 3x2 for 6 and 7x2 for 14.
There is a set of 2's so you take one and cross out the other. Now take 3 and 7 since this is LCM we keep the remaining.
7x3x2=42
42th visit 
*42nd

You have to list the factors

So 42th person