math
posted by Matthew
Ellis plans to hand out door prizes as the guest arrive she has 256 guests every 6th guest will receive a mug and for every 14 guests will receive a t shirt. Which guest will be the first to receive both mug and at shirt? Next question is elli has 8 and 1/2 pound bags of mints. She plans to put 1/12 pound at each place setting. will she have enough mints? PLEASE HELP I TRIED so hard and I can't get the answer thank you so much I need help with the answer before tomorrow morning!!!!!!!!!

Steve
LCM(6,14) = 42, so the 42nd guest will receive both.
For the mints, 256 guests at 1/12 lb/guest shows she needs
256/12 = 21.33 lbs of mints
8 1/2 lbs only serves 102 guests (8*12 + 6) 
Sam
For the first one:
if you have to, just list em all out
Mugs: 6,12,18,24,30,36,42,48,54,60....
Shirts: 14,28,42,56,70....
See any numbers in common so far? Yep: the 42. So the 42nd guest will get both
Second one: Can't figure it out, cuz not enough information, did you leave something out, like how many place settings there are? 
Sam
Yeah what Steve said

Name
No she won't have enough

Name
I agree with sam

Someone
You have to find the LCM=Least Common Multiple.
So if your prime factorize 6 and 14 you will get 3x2 for 6 and 7x2 for 14.
There is a set of 2's so you take one and cross out the other. Now take 3 and 7 since this is LCM we keep the remaining.
7x3x2=42
42th visit 
Someone
*42nd

Name
You have to list the factors

Name
So 42th person
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