Math
posted by Jessy
Factor:
(x^3)(z^6)27y^9
81x^416y^4
2x^3+16y^3

Steve
You have the usual sum/difference of squares/cubes.
(xz^2)^3  (3y^3)^3
= (xz^23y^3)((xz^2)^2 + (xz^2)(3y^3) + (3y^3)^2)
Similarly, the others are
(9x^2)^2  (4y^2)^2
and
2(x^3 + (2y)^3)
Just apply your formulas. If you get stuck, come on back and say where.
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