posted by Anonymous .
Nitric acid reacts with silver metal:
4HNO3+3Ag yields NO+2H2O+3 AgNO3.
Calculate the number of grams of NO formed when 10.8 g of Ag reacts with 12.6g of HNO3.
This is a limiting reagent (LR) problem. You know that because amounts are given for BOTH reactants.
mols Ag = grams/atomic mass = ?
mols HNO3 = grams/molar mas = ?
Using the coefficients in the balanced equation, convert mols Ag to mols NO formed.
Do the same for mols HNO3 to mols NO.
It is likely that you will have two different values for mols NO which means one of the values is wrong. The correct value in LR problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Now taker the smaller value for mols and convert to grams. g = mols x molar mass.