Physics
posted by JAY Z .
A snowboarder of mass 87.1 kg (including all of the gear and clothing), starting with a downhill speed of 6.1 m/s, slides down a slope at an angle $\theta$ of 36.7° with the horizontal. The coefficient of kinetic friction is 0.106. What is the net work done on the snowboarder in the first 8.02 s of descent?

Physics 
Henry
Fs = m*g = 87.1kg * 9.8N/kg = 853.6 N. =
Force of snowboarder.
Fp = 853.6*sin36.7 = 510.1 N. = Force parallel to hill.
Fn = 853.6*cos36.7 = 684.4 N = Normal =
Force perpendicular to hill.
Fk = u*Fn = 0.106 * 684.4 = 72.55 N. =
Force of kinetic friction.
a=(FpFk)/m=(510.172.55)/87.1=5.02 m/s^2.
d = Vo*t + 0.5a*t^2
d = 6.1*8.02 + 2.51*8.02^2 = 210.4 m.
Down the slope.
Work = F*d = (510.172.55) * 210.4 =
92,061 Joules.
Respond to this Question
Similar Questions

eng physics
in a downhill race a skier slides down a 40 degree slope. starting from rest how far must he slide down the slope to reach a speed of 130 km/hr. ignore air friction and assume the co effiecnt of kinetic friction between skies and snow … 
physics
a snowboarder moves down a slope for which theta= 22 degrees. the coefficient of kinetic friction between the board and the snow is 0.21 and her velocity is a constant 8.3 m/s. what will her speed 100 meters past the end of the slope? 
physics
A snowboarder of mass 71.8 kg (including gear and clothing), starting with a speed of 4.8 m/s, slides down a slope at an angle θ = 37.1° with the horizontal. 
physics
A snowboarder of mass 74.4 kg (including gear and clothing), starting with a speed of 5.0 m/s, slides down a slope at an angle è = 37.1° with the horizontal. The coefficient of kinetic friction is 0.116. What is the net work done … 
Physics
A sled is being held at rest on a slope that makes an angle (theta) with the horizontal. After the sled is released, it slides a distance (d1) down the slope and then covers the distance (d2) along the horizontal terrain before stopping. … 
Physics
A skier of mass 79.1 kg, starting from rest, slides down a slope at an angle q of 38 with the horizontal. The coefficient of kinetic friction, m, is 0.09. What is the net work (the net gain in kinetic energy) done on the skier in the … 
physics
A skier of mass 77.7 kg, starting from rest, slides down a slope at an angle $\theta$ of 35.7° with the horizontal. The coefficient of kinetic friction is 0.08. What is the net work, i.e. net gain in kinetic energy, (in J) done on … 
physics
A skier of mass 70.4 kg, starting from rest, slides down a slope at an angle $\theta$ of 36.8° with the horizontal. The coefficient of kinetic friction is 0.14. What is the net work, i.e. net gain in kinetic energy, (in J) done on … 
physics
A skier of mass 70.4 kg, starting from rest, slides down a slope at an angle $\theta$ of 36.8° with the horizontal. The coefficient of kinetic friction is 0.14. What is the net work, i.e. net gain in kinetic energy, (in J) done on … 
physics
A skier of mass 70.4 kg, starting from rest, slides down a slope at an angle $\theta$ of 36.8° with the horizontal. The coefficient of kinetic friction is 0.14. What is the net work, i.e. net gain in kinetic energy, (in J) done on …