Statistics
posted by HELP .
Of the parts produced by a particular machine, 1.5% are defective. If a random sample of 11 parts produced by this machine contains 2 or more defective parts, the machine is shut down for repairs. Find the probability that the machine will be shut down for repairs based on this sampling plan.

1p(x = 0) + p(x = 1)
1[(11C0)(.015)^0(.985)^11 + 11C1 *0.015^1 *.985^10)]
1[.84684 + .14185]
1.9887 = 0.0113