Math
posted by Amanda .
Suppose a baseball player had 211 hits in a season. In the given probability distribution, the random variable X represents the number of hits the player obtained in the game.
x P(x)
0 0.1879
1 0.4106
2 0.2157
3 0.1174
4 0.0624
5 0.0060
a.) Compute and interpret the mean of the random variable X
b.) Compute the standard deviation of the random variable X.

To calculate the mean we add up all of the numbers and divide by the total number amount for e.g. you have 5 numbers here. Add them up and divide by 5
b) The standard deviation is that complicating equation. You can check this on google to get the exact formula and i think if you type in standard deviation calculator you can plug in the numbers on the website and check this with your answer 
µ= x * p(x)
= 0(0.11879) + 1( 0.4106) + 2(0.2157) + 3(0.1174) + 4 (0.0624) + 5(0.0060) = ?
σ^2 = x^2 * p(x)
= 0^2(0.11879) + 1^2(0.4106) + 2^2(0.2157) + 3^2(0.1174) + 4^2(0.0624) + 5^2(0.0060) = ?
sd = sqrt( σ^2 (µ^2)) 
Suppose a baseball player had 212 hits in a season. In given probability distribution, the random variable X represents the number of the player obtained in a game
0 0.0908
1 0.4677
2 0.2988
3 0.1163
4 0.0147
5 0.0117
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