Math
posted by Aaron .
1) The hypotenuse of an isosceles right triangle is 8 cm longer than either of its legs. Note that an isosceles right triangle is a right triangle whose legs are the same length. Find the exact length of its legs and its hypotenuse.
2) The length of a rectangle is 9 m longer than its width and the area of the rectangle is 280 m2. Find the exact dimensions of the rectangle.
3) The first leg of a right triangle is 3 cm longer than its second leg. If the hypotenuse has a length of 8 cm, find the exact lengths of the two legs

if the legs are x and the hypotenuse is h, then
h^2 = x^2+x^2
(x+8)^2 = 2x^2
x^2+16x+64 = 2x^2
x^2  16x  64 = 0
Now just use the quadratic formula
If the width is w, then
w(w+9) = 280
If the shorter leg is x, then
x^2 + (x+3)^2 = 8^2 
x=8

1.C
2.D
3.A
4.C
5.A
6.5
7.B
8. x,y=1.7*2+31=4.5
The drummer final position was 4.5 
I got 2/8. U need to show it better.😣

What are the answers?
I need them desperately!!! 
Im 100% right :)
BTW for question 8 I'll give you the answer for it...
1.C 15 cm
2.D 12. cm
3.A Q
4.C 10
5.A II
6.A (8, 10)
7.B 5
8. A: (x,y) > (x + 1, y + 3)
B: (2, 5) > (2 + 1, 5 + 3) = (1, 2)
100% right... you are welcome that I even gave you the answers lol. anyways 100% right :)no lie 
thx Kaiipapa 100% right

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100% Correct

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i got 5/8 she is wrong

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1.C
2.D
3.A
4.C
5.B
6.A
7.A
8.B
9.A(x,y) > (x + 1, y + 3)
B(2, 5) > (2 + 1, 5 + 3) = (1, 2) 
This website is scaring me.

ME ) is correct I got a 100%

Thanks so much ME

Jiskha is the Best thanks you so much!!!!!

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