posted by Aaron .
1) The hypotenuse of an isosceles right triangle is 8 cm longer than either of its legs. Note that an isosceles right triangle is a right triangle whose legs are the same length. Find the exact length of its legs and its hypotenuse.
2) The length of a rectangle is 9 m longer than its width and the area of the rectangle is 280 m2. Find the exact dimensions of the rectangle.
3) The first leg of a right triangle is 3 cm longer than its second leg. If the hypotenuse has a length of 8 cm, find the exact lengths of the two legs
if the legs are x and the hypotenuse is h, then
h^2 = x^2+x^2
(x+8)^2 = 2x^2
x^2+16x+64 = 2x^2
x^2 - 16x - 64 = 0
Now just use the quadratic formula
If the width is w, then
w(w+9) = 280
If the shorter leg is x, then
x^2 + (x+3)^2 = 8^2
The drummer final position was 4.5
I got 2/8. U need to show it better.😣
What are the answers?
I need them desperately!!!
Im 100% right :)
BTW for question 8 I'll give you the answer for it...
1.C 15 cm
2.D 12. cm
6.A (-8, -10)
8. A: (x,y) ----> (x + 1, y + 3)
B: (-2, -5) ---> (-2 + 1, -5 + 3) = (-1, -2)
100% right... you are welcome that I even gave you the answers lol. anyways 100% right :)no lie
thx Kaiipapa 100% right
Your welcome anytime
Yea thanks I pass it thank you so much