Pre calculus
posted by Anonymous .
Solve for all values between zero and 360 degrees.
cos(theta42 degrees)=1
What is the general solution and what is the solution????

cos(Ø  42°) = 1
I know cos 180° = 1
Ø  42 = 180
Ø = 222° , only one solution between 0° and 360°
(look at the graph of cos Ø )
The period of cos(Ø42) is 360°
so a general solution is
Ø = 222° + 360k° , where k is an integer.