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A capacitor has circular plates of radius \(r = 12\,cm\) that are now a distance \(d = 0.2\,cm\) apart.

If this particular capacitor is hooked up to a \(12\,V\) battery, what is the value of the Electric Field between the two plates in \(N/C\)?

  • physics -

    q=CU = ε₀AU/d
    E=σ/2ε₀ =q/A•2ε₀=
    = ε₀AU/d•A•2ε₀=U/d

    The same result may be obtained from
    E=-gradΔU =>
    E=ΔU/Δx =U/d

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