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if 3e charge is at the origin and magnesium nucleus is 3 cm from the origin in the x-direction. what is the magnitude of the net force a boron nucleus would experience half way between magnesium nucleus and 3 e charge

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    q₁ = 3 e,
    q₂ = 12e,
    q₃ = 5e
    The electric field at the midpoint is
    E= kq₂/(x/2)²- kq₁/(x/2)²=
    =k(12e-3e)/(x/2)² =k36e/x² (directed to the 3e charge)
    F= q₃E=k36e•5e/x²=
    =k•180e/x²,
    where
    k =9•10⁹ N•m²/C²,
    e =1.6•10⁻¹⁹ C,
    x is the distance between 3e and 12e

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